Home
Class 11
PHYSICS
An organ pipe of (3.9 pi) mlong, open at...

An organ pipe of `(3.9 pi) m`long, open at both ends is driver to third harmonic standing wave. If the amplitude of pressure oscillation is `1%` of mean atmospheric pressure `[p_(o) = 10^(5) N//m^(2)]`. The [Given, velocity of sound `= 200 m//s` and density of air `= 1.3 kg//m^(3)]`

A

`2.5 cm`

B

`5 cm`

C

`1 cm`

D

`2 cm`

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta p_(max) = BAk` ..(i)
`nu = sqrt((B)/(rho))`
:. `B = rho nu^(2)`
`l = (3 lambda)/(2)`
:. `lambda = (2l)/(3)`
`k = (2 pi)/(lambda) = (2 pi)/(2l//3) = (3 pi)/(l)`
`= (3 pi)/(3.9 pi) = (1)/(1.3) m^(-1)`

Subsiting in Eq. (i), we have
`A = (Delta p _(max))/(BK) = (Delta p_(max))/(rho nu^(2)k`
`= ((0.01 xx 10^(5)))/(1.3 xx (200)^(2) xx (1//1.3)`
`= 0.025 m = 2.5 cm`
Promotional Banner

Topper's Solved these Questions

  • SOUND WAVES

    DC PANDEY|Exercise Single correct option|1 Videos

  • SOUND WAVES

    DC PANDEY|Exercise Level 2 More Than One Correct|5 Videos

  • SOUND WAVES

    DC PANDEY|Exercise Subjective Questions|1 Videos

  • SOLVD PAPERS 2017 NEET, AIIMS & JIPMER

    DC PANDEY|Exercise Solved paper 2018(JIPMER)|38 Videos

  • SUPERPOSITION OF WAVES

    DC PANDEY|Exercise Level 2 Subjective|8 Videos

Similar Questions

Explore conceptually related problems

A 3 m long organ pipe open at both ends is driven to third harmonic standing wave. If the ampulitude of pressure oscillations is 1 per cent of mean atmospheric pressure (p_(o) = 10^(5) Nm^(2)) . Find the ampulited of particle displacement and density oscillations. Speed of sound upsilon = 332 m//s and density of air rho = 1.03 kg//m^(3) .

What is the density of a gas at N.T.P. if the rms velocity of the gas molecules is 400m//s ? (Take atmospheric pressure P = 1xx10^(5)N//m^(2) )

Calculate the amplitude of vibrations of air particles when a wavee of intensity 10^(-3) "watt"//m^(2) is produced by a tuning fork of frequency 540 Hz. Velocity of sound in air = 340 m s^(-1) and density of air = 1.3 kg m^(-3)

A pipe 30 cm long, is open at both ends. Which harmonic mode of the pipe resonates a 1.1 kHz source? (Speed of sound in air = 330 m s^(-1) )

A sound wave having a frequency of 100 Hz and pressure amplitude of 10 pa, then calculate the displacement amplitude (Given speed od sound in air = 340 m/s and density of air = 1.29 kg/m^(3) )

The U-tube acts as a water siphon. The bend in the tube is 1m above the water surface. The tube outlet is 7m below the water surface. The water issues from the bottom of the siphon as a free jet at atmospheric pressure. Determine the speed of the free jet and the minimum absolute pressure of the water in the bend. Given atmospheric pressure =1.01xx 10^(5)N//m^(2),g=9.8 m//s^(2) and density of water =10^(3)kg//m^(3) .

An organ pipe is open at both ends. It is producing sound at its third harmonic, the frequency of which is 262 Hz. The speed of sound is 343 m/s. What is the length of the pipe?

If the density of oxygen is 1.44 kg//m^(3) at pressure of 10^(5)N//m^(2) , then the root-mean-square velocity of oxygen molecules in m/s will be

A sound wave in air has a frequency of 300 H_(Z) and a displacement ampulitude of 6.0 xx10^(-3) mm . For this sound waves calculate the (a) Pressure ampulitude (b) intensity (c ) Sound intensity level (in dB) Speed of sound = 344 m//s and density of air = 1.2 kg//m^(3) .