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A sounding body emitting a frequency of ...

A sounding body emitting a frequency of `150 H_(Z)` is dropped from a height. During its fall under gravity it crosses a balloon moving upwards with a constant velocity of `2 m//s` one second after it started to fall . The difference in the frequency observer by the man in balloon just before and just afer crossing the body will be (velocity of sound `= 300 m//s`, `g = 10 m//s^(2))`

A

`12`

B

`6`

C

`8`

D

`4`

Text Solution

Verified by Experts

The correct Answer is:
A
Velocity of source after `1 s`,
`nu_(s) = gt = 10 xx 1 = m//s`
`Delta f = f ((nu + nu_(o))/(nu - nu_(s))) - f ((nu - nu_(o))/(nu + nu_(s)))`
`= 150 ((300 + 2)/(300 - 10)) - 150 ((300 - 2)/(300 + 10))`
`= 12 H_(Z)`
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