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The pressure variation in a sound wave i...

The pressure variation in a sound wave in air is given by
`Deltap = 12 sin (8.18X - 2700 t + pi//4) N//m^(2)`
find the displacement amplitude. Density of air `= 1.29 kg//m^(3)`.

Text Solution

Verified by Experts

The correct Answer is:
A, D
In the above problem, we have found that
`A = (Delta p_(max))/(2 pi f rho nu)`
`= ((Delta p_(max)k))/(rho omega^(2))` (as `nu = (omega)/(k)` and `2 pi f = omega`)
Now subsituting the value, we have
`A= ((12)(8.18))/((1.29)(2700)^(2)) = 1.04 xx 10^(-5)m`
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