Home
Class 11
PHYSICS
The faintest sound that can be heard has...

The faintest sound that can be heard has a pressure ampulitude of about `2 xx 10^(-5) N//m^(2)` and the loudest that can be heard without pain has a pressure ampulited of about `28 N//m^(2)`. Dentermine in each (a) the intensity of the sound both in `w//m^(2)` and in `dB` and (b) the ampulited of the oscillations if the frequency is `500 H_(Z)`. Assume an air density of `1.29 kg//m^(3)` and a velocity of sound is `345 m//s`.

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D

`I = (nu(Deltap)^(2)max)/(2B)`
`= ((Deltap)^(2)max)/(2B)`
For finest sound,
`I = (2 xx 10^(-5))^(2)/(2 xx 129 xx 345)`
`= 4.49 xx 10^(-13) W//m^(2)`
`L = 10 log ((I)/(I_(0)))`
`= 10 log_(10) ((4.49 xx 10^(-13))/(10^(-12)))`
`= - 3.48 dB`
Same formulae can be applied for loudest sound.
(b) `(Delta p)_(max) = BAK`
`= (rho nu)^(2) (A) ((omega)/(nu))`
`= 2 pi f rho nu`
:. `A = (Deltap)_(max)/(2 pi f rho nu)`
For finest sound,
`A = (2 xx 10^(-5))/((2 pi)(500)(1.29)(345)`
`= 1.43 xx 10^(-11) m`
Promotional Banner

Topper's Solved these Questions

  • SOUND WAVES

    DC PANDEY|Exercise Exercise 19.4|2 Videos
  • SOUND WAVES

    DC PANDEY|Exercise Exercise 19.5|5 Videos
  • SOUND WAVES

    DC PANDEY|Exercise Exercise 19.2|4 Videos
  • SOLVD PAPERS 2017 NEET, AIIMS & JIPMER

    DC PANDEY|Exercise Solved paper 2018(JIPMER)|38 Videos
  • SUPERPOSITION OF WAVES

    DC PANDEY|Exercise Level 2 Subjective|8 Videos

Similar Questions

Explore conceptually related problems

What is the amplitude of motion for the air in the path of a 60 dB , 800 H_(Z) sound wave? Assume that rho_(air)= 1.29 kg//m^(3) and upsilon = 330 m//s .

For a person with normal hearing, the faintest sound that can be at a frequency of 400 Hz has pressure amplitude of about 6.0 xx 10^(-5) Pa . Calculate the corresponding intensity in W//m^(2) . Take speed of sound in air as 344 m//s and density of air 1.2 kg//m^(3) .

A sound wave of frequency 280 Hz has an intensity of 1.00 W//m2 ? What is the amplitude of the air oscillations caused by this wave?

The pressure amplitude in a sound wave from a radio receive is 2.0 xx 10^(-3)N//m^(2) and the intensity at a point is 10^(-6)W//m^(2) . If by turning the "Volume" knob the pressure amplitude is increased to 3 xx 10^(-2)N//m^(2) , evalute the intensity.

A typical loud sound wave with a frequency of 1 Kh_(Z) has a pressure amplitude of about 10 Pa (a) At t = 0 , the pressure is a maximum at some point X_(1) . What is the displacement at that point at t = 0 ? (b) What is the maximum value of the displacement at any time and place/ Take the density of air to be 1.29 kg//m^(3) and speed of sound in air is 340 m//s .

A sound wave in air has a frequency of 300 H_(Z) and a displacement ampulitude of 6.0 xx10^(-3) mm . For this sound waves calculate the (a) Pressure ampulitude (b) intensity (c ) Sound intensity level (in dB) Speed of sound = 344 m//s and density of air = 1.2 kg//m^(3) .

At a pressure of 10^(5)N//m^(2) , the volumetric strain of water is 5xx10^(-5) . Calculate the speed of sound in water. Density of water is 10^(3)kg//m^(3).

The rms velocity molecules of a gas of density 4 kg m^(-3) and pressure 1.2 xx 10^(5) N m^(-2) is