A tuning fork of unknows frequency makes three beats per second with a standard fork of frequency `384 H_(Z)`. The beat frequency decreases when a small piece of wax is put on a prong of the first fork. What is the frequency of this fork?
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The correct Answer is:
C
By putting wax on first tuning fork, its frequency will decrease. Beat frequency is also decreasing. Hence, `f_(1) gt f_(2)` `:. f_(1) - f_(2) = 3` or `f_(1) = 3 + f_(2) = 3 + 384` `= 387 H_(Z)`
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