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A glass beaker holds exactly 1 L "at" 0^...

A glass beaker holds exactly `1 L "at" 0^@ C`
(a) What is its volume at `50^@ C` ?
(b) If the beaker is filled with mercury at `0^@ C`, what volume of mercury overflows ehen the temperature is `50^@ C` ? `alpha _ g = 8.3 xx 10^-6 per ^@ C` and` gamma_Hg = 1.82 xx 10^-4 per ^@ C`.

Text Solution

Verified by Experts

The correct Answer is:
A, B
(a) The volume of beaker after the temperature change is
`V_(beaker) =V_0(1 + 3 alpha_g Deltatheta)`
= `(1)[1+ 3 xx 8.3 xx 10^-6 xx 50]`
=`1.001 L`
(b) volume of mercury at `50^@ C` is
`V_(mercury) = V_0(1 +gamma_Hg Delta theta)`
= `(1)[1 +1.82 xx 10^-4 xx 50]`
= `1.009 L`
The overflow is thus `1.009 - 1.0001 = 0.008 L or 8 mL`.
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