Prove that the pressure of an ideal gas is numerically equal to two third of the mean translational kinetic energy per unit volume of the gas.

Answer

A

Explanation

Translational (KE) per unit volume
` E = 1/2 ("mass per unit volume") (v barr ^2)`
=` 1/2 (rho) ((3 p)/ rho) = 3/2 p`
or `p = 2/3 E`.