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An iron ball has a diameter of 6 cm and ...

An iron ball has a diameter of `6 cm` and is `0.010 mm` too large to pass through a hole in a brass plate when the ball and plate are at a temperature of `30^@ C`. At what temperature, the same for ball and plate, will the ball just pass through the hole?
Take the values of (prop) from Table `20 .2`.

Text Solution

Verified by Experts

The correct Answer is:
C
`Delta d = d(alpha_B - alpha_(Fe)) Delta theta`
:. `Delta theta = (Delta d)/(d(alpha _B -alpha_(Fe))`
= `(0.01)/(60 xx 0.8 xx 10^-5)= 20.83^@ C`
`:.` New temperature `= (30 + 20.83) = 50.83^@ C`
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