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The cyclic process for 1 mole of an idea...

The cyclic process for 1 mole of an ideal gas is shown in the V-T diagram. The work done in AB, BC and CA respectively is

A

(a) 0, `RT_(2)In|V_2/V_1|,R(T_1-T_2)`

B

(b) `R(T_1-T_2),0,RT_(1)In|V_1/V_2|`

C

(c) `0,RT_(1)In|V_1/V_2|,R(T_1-T_2)`

D

(d) 0,RT_(2)In|V_2/V_1|,R(T_2-T_1)`

Text Solution

Verified by Experts

The correct Answer is:
A

For AB V=constant
`therefore W=0`
For BC `W=nRT_(2)In(V_f/V_i)`
`=RT_2In(V_2/V_1)`
For CA `VpropT`
`:.` p=constant
`W=nRDeltaT`
`=R(T_1-T_2)`
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