One mole of an ideal gas is taken through a cyclic process. The minimum temperature during the cycle is 300K. Then, net exchange of heat for complete cycle is

Options

A. `600R ln 2`
B. `300R ln2`
C. `-300Rln2`
D. `900Rln2`

Answer

B

Explanation

`TpropU`
`T_C=T_D=T_0=300K`
`T_A=T_B=2T_0=600K`
`Q_(n et) = Q_(AB)+Q_(BC)+Q_(CD)+Q_(DA)`
`=nRT_A In(V_f/V_i)+nC_V(T_C-T_B)+nRT_C In(V_f/V_i)+nC_V(T_A-T_D)`
`=(1)(R)(600) In(2)+(1)(C_V)(-300)+(1)(R)(300) In(1/2)+(1)(C_V)(300)`
`=300RIn2`