One mole of an ideal gas at temperature `T_` expands slowly according to the law `p/V=` constant.
Its final temperature is `T_2`. The work done by the gas is

Options

A. (a) `R(T_2-T_1)`
B. (b) `2R(T_2-T_1)`
C. (c) `R/2(T_2-T_1)`
D. (d) `(2R)/(3)(T_2-T_1)`

Answer

C

Explanation

`pV^-1=` constant
In the process, `pV^x=` constant
`W=((R)/(1-x))DeltaT`
Here, `x=-1`
`:.` `W=R/2DeltaT=R/2(T_2-T_1)`