Pressure p, volume V and temperature T for a certain gas are related by
`p=(alphaT-betaT^2)/(V)`
where, `alpha` and `beta` are constants. Find the work done by the gas if the temperature changes from `T_1` to `T_2` while the pressure remains the constant.

Answer

A, B

Explanation

`p=(alphaT-betaT^2)/(V)` (p=constant)
Hence `V=(alphaT-betaT^2)/(p)`
or `dV=((alpha-2betaT)/(p))dT`
`W=intpdV=int_(T_1)^(T_2)p((alpha-2betaT)/(p))dT`
or `W=[alphaT-betaT^2]_(T_1)^(T_2)`
`=alpha(T_2-T_1)-beta(T_2^2-T_1^2)`