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At 1 atmospheric pressure, 1.000 g of w...

At 1 atmospheric pressure, 1.000 g of water having a volume of `1.000 cm^3` becomes 1671 `cm^3` of steam when boiled. The heat of vaporization of water at 1 atmosphere is `539 cal//g` . What is the change in internal energy during the process?

A

`468.2 cal`

B

`258.5 cal`

C

`498.5 cal`

D

`378.5 cal`

Text Solution

Verified by Experts

The correct Answer is:
C
Heat spent during vaporisation,
`Q=mL = 1.000 xx 539 = 539 cal`
Work done, `W= P(V_v-V_l)`
`=1.013 xx (10^5) xx (1671 - 1.000) xx (10^-6)`
`=169.2 J = (169.2)/(4.18)cal `
=40.5 cal
`:.` Change in internal energy,
`:. DeltaU = 539 cal - 40.5 cal`
= 498.5 cal` .
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