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At 1 atmospheric pressure, 1000 g of wat...

At 1 atmospheric pressure, 1000 g of water having a volume of `1000 cm^3` becomes `1.097 cm^3` of ice on freezing. The heat of fusion of water at 1 atmosphere is `80.0 cal//g`. What is the change in internal energy during the process?

Text Solution

Verified by Experts

The correct Answer is:
A, B, C
Heat given out during freezing,
`Q = -mL = -1 xx 80 = -80 cal`
External work done `W = P (V_(ice)-V_(water))`
`=1.013 xx (10^5 ) xx (1.091 - 1000) xx (10^-6)`
`= 9.22 xx (10^-3) J`
`= (9.22 xx (10^-3))/4.18 cal
`= 0.0022 cal`
`:. Change in internal energy,
`Delta U = Q-W = -80-0.0022`
`=-80.0022` cal .
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