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Three rods each of same length and cross...

Three rods each of same length and cross - section are joined in series. The thermal conductivity of the materials are K, 2K and 3K respectively. If one end is kept at `200^@C` and the other at `100^@C`. What would be the temperature of the junctions in the steady state? Assume that no heat is lost due to radiation from the sides of the rods.

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D


`H_(1)=H_(2)=H_(3)`
`:. (200-theta_(1))/((1//KA))=(theta_(1)-theta_(2))/((l//2KA))=(theta_(2)-100)/((l//3KA))`
Solving these equations we get,
`theta_1 = 145.5^@C`
and `theta_2 = 118.2^@C` .
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