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A rod CD of thermal resistance 5.0KW(-1)...

A rod `CD` of thermal resistance `5.0KW_(-1)` is joined at the middle of an identical rod `AB` as shown in figure. The ends `A`,` B` and `D` are maintained at `100^(@)C` , `0^(@)C` and `25^(@)C` respectively. Find the heat current in `CD`.

Text Solution

Verified by Experts

The correct Answer is:
D

`H_1 + H_2 = H_3`
`(100-theta)/(R//2) + (25-theta)/R = (theta-0^@)/(R//2)`
Solving we get, `theta = 45^@C`
`H_(CD) = (TD)/R = ((45^@C - 25^@c)/5)`
`= 4W` .
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