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A thin square steel plate 10 cm on a sid...

A thin square steel plate 10 cm on a side is heated in a black smith's forge to temperature of `800^@C`. If the emissivity is 0.60, what is the total rate of radiation of energy ?

Text Solution

AI Generated Solution

To find the total rate of radiation of energy from the thin square steel plate, we can use Stefan-Boltzmann Law, which states that the power radiated by a black body is proportional to the fourth power of its absolute temperature. The formula for the power radiated is given by: \[ P = \sigma \cdot E \cdot A \cdot T^4 \] Where: - \( P \) = total power radiated (in watts) - \( \sigma \) = Stefan-Boltzmann constant \( \approx 5.67 \times 10^{-8} \, \text{W/m}^2\text{K}^4 \) - \( E \) = emissivity of the material (dimensionless) ...
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Knowledge Check

  • A thin square steel plate with each side equal to 10 cm is heated by a blacksmith. The rate of radiated energy by the heated plate is 1134 W . The temperature of the hot steel plate is (Stefan's constant sigma = 5.67 xx10^(-8) " watt "m^(-2) K^(-4) , emissivity of the plate = 1)

    A
    1000 K
    B
    1189 K
    C
    2000 K
    D
    2378 K

  • The temperature of the sun is 6000 K and is treated as a black body. The solar heat energy radiated by the sun is 10^(9)W//m^(2) . What is the temperature of a black body if it radiated heat energy of 10^(5)W//m^(2) ?

    A
    `227^(@)C`
    B
    `27^(@)C`
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    D
    `400^(@)C`

  • Consider a black body radiation in a cubical box at absolute temperature T. If the lengh of each side of the box is doubled and the temperature of the walls of the box and that of the radiation is halved then the total energy

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    B
    doubles
    C
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