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Two liquids of specific heat ratio 1:2 a...

Two liquids of specific heat ratio 1:2 are at temperature `2theta and theta`

A

if equal amounts of them are mixed, then temperature of mixture is `1.5 theta`

B

if equal amounts of them are mixed, then temperature of mixture is `4/3 theta`

C

for their equal amounts, the ratio of heat capacities is 1:1

D

for their equal amounts, the ratio of their heat capacities is 1:2.

Text Solution

Verified by Experts

The correct Answer is:
B, D
`ms (2theta - theta') = m (2s)(theta'-theta)`
Solving this equation we get,
`theta' = 4/3 theta`
Further, heat capacity
`C = ms or C prop s ` (as m is same)
`:. C_1/C_2 = s_1/s_2 = 1/2` .
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