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One end of a uniform brass rod 20 cm lo...

One end of a uniform brass rod 20 cm long and `10 cm^2` cross-sectional area is kept at `100^@C`. The other end is in perfect thermal contact with another rod of identical cross-section and length 10 cm. The free end of this rod is kept in melting ice and when the steady state has been reached, it is found that 360 g of ice melts per hour. Calculate the thermal conductivity of the rod, given that the thermal conductivity of brass is `0.25 cal//s cm^@C and L = 80 cal//g`.

Text Solution

Verified by Experts

The correct Answer is:
A, B, C
`L ((dm)/(dt)) = (TD)/(R_1+R_2)`

or `(80 xx 360)/3600 = (100)/(20/(0.25 xx 10) + (10)/(K xx 10))`
Solving this equation, we get
`K = 0.222 cal//cm-s-^@C`.
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