In the circuit shown in figure find

a. The power supplied by 10 V battery
b. The power consumed by `4 V` battery and
c. The power dissipated in `3Omega` resistance.

Explanation

Net emf of the circuit `=(10-4)V-6V`
`:.` Current in the circuit
`i=("netemf")/("total resistance")=6/3=2A`
a. Power supplied by `10 V` battery `=Ei=(10)(2)=20W`
b. Power consumed by `4 V` battery `=Ei(4)92)=8W`
c. Power consumed be `3Omega` resistance `=i^2R(2)^2(3)=12W`