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The potential difference between two poi...

The potential difference between two points in a wire `75.0 cm` apart is `0.938 V`, when the current density is `4.40 xx 10^7 A// m^2`. What is
(a) the magnitude of `E` in the wire?
(b) the resistivity of the material of which the wire is made?

Text Solution

Verified by Experts

The correct Answer is:
A, B, D
a. `E=V/l=0.938/0.75=1.25V/m`
b. `E=Jrho`
`:. rho=E/J=1.25/(4.4xx10^7)`
`=2.84xx10^-8Omega-m`
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