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An electric field of 10^5 N//C points du...

An electric field of `10^5 N//C` points due west at a certain spot. What are the magnitude and direction of the force that acts on a charge of `+2muC and -5muC` at this spot?

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The correct Answer is:
A, B, D

Force on `+2muC=qE=(2xx10^-6)(10^5)`
`=0.2N` (due west)
Force on `-5muC=(5xx10^-6)(10^5)`
`=0.5N` (due east)
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