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A uniform electric field E0 is directed ...

A uniform electric field `E_0` is directed along positive y-driection. Find the change in electric potential energy of a positive test charge `q_0` when it is displaced in this field from `y_i=a` to `y_f=2a` along the y-axis.

A

`-q_0E_0a`

B

`q_0E_0a`

C

`(-q_0E_0)/a`

D

`(q_0E_0)/a`

Text Solution

Verified by Experts

The correct Answer is:
A
Electrostatic force on the test charge,
`F_e=q_0E_0` (along positive y-direction)
`:. W_(i-f)=-/_\U`
`or /_\U=-W_(i-f)=[q_0E_0(2a-a)]`
`=-q_0E_0a`
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