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A point charge q1 =1.0muC is held fixed ...

A point charge `q_1 =1.0muC` is held fixed at origin. A second point charge `q_2 = -2.0 muC` and a mass `10^-4` kg is placed on the x-axis, 1.0 m from the origin. The second point charge is released from rest. What is its speed when it is 0.5 m from the origin?

Text Solution

Verified by Experts

The correct Answer is:
A
`K_i+U_i=K_f+U_f`
`:. 1/(4piepsilon_0)(q_1q_2)/r_i=1/2mv^2+1/(4piepsilon_0) (q_1q_2)/r_f`
`:.v=sqrt(2/m(1/(4piepsilon_0))(q_1q_2)(1/r_i-1/r_f)))`
`sqrt(2/10^-4(9xx10^9)(-2xx10^-12)(1/1.0-1/0.5))`
`=18.97m//s`
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