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Two points charges q1 and q2 are placed ...

Two points charges `q_1 and q_2` are placed at a distance of 50 m from each each other in air, and interact with a certain force. The same charges are now put in oil whose relative permittivity is 5. If the interacting force between them is still the same, their separation now is

A

`16.6m`

B

`22.3m`

C

`28.4m`

D

`25.0m`

Text Solution

Verified by Experts

The correct Answer is:
B

`1/(4piepsilon_0).(q_1q_2)/r_1^2=1/(4piepsilon_0k).(q_1q_2)/r_2^2)`
`:. r_2=r_1/sqrtk=50/sqrt5`
`=22.36m`
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