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An infinite line of charge lamda per uni...

An infinite line of charge `lamda` per unit length is placed along the y-axis. The work done in moving a charge q from `A(a,0)` to `B (2a,0)` is

A

`(q lamda)/(2piepsilon_0) `"ln" 2`

B

`(qlamda)/(2piepsilon_0)"ln" (1/2)`

C

`(qlamda)/4piepsilon_0) "ln" sqrt2`

D

`(qlamda)/(4piepsilon_0) "ln"2`

Text Solution

Verified by Experts

The correct Answer is:
B
`W_(ArarrB)=q(V_B-V_A)`
`=q[-int_A^BEdr]=q int_B^A Edr`
`=q int_(2a)^a lamda/(2piepsilon_0)dr= (qlamda)/(2piepsilon_0) "in" (1/2)`
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DC PANDEY-ELECTROSTATICS-Level 1 Objective
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