A charged particle of mass `m = 1` kg and charge `q = 2muC` is thrown from a horizontal ground at an angle `theta = 45^@` with the speed `25 m//s`. In space, a horizontal electric field `E = 2 xx 10^7` V/m exists in the direction of motion. Find the range on horizontal ground of the projectile thrown. Take `g = 10 m//s^2`.

Answer

A, B, C

Explanation

`T=(2usintheta)/g=(2xx25xxsin45^@)/10=5/sqrt2s`
`R=S_x=u_xT+1/2a_xT^2`
`=(ucos45^@)(T)+1/2((qE)/m)T^2`
`=(25)(1/sqrt2)(5/sqrt2)+((2xx10^-6xx2xx10^7)/1)(5/sqrt2)^2`
`=62.5+250=312.5m`