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The electric field in a region is given ...

The electric field in a region is given by `E = 3/5 E_0hati +4/5E_0j` with `E_0 = 2.0 x 10^3 N//C`. Find the flux of this field through a rectangular surface of area `0.2 m^2` parallel to the y-z plane.

A

`24Nm^2//C`

B

`240Nm^2//C`

C

`440Nm^2//C`

D

`44Nm^2//C`

Text Solution

Verified by Experts

The correct Answer is:
B
`S=(0.2)hati`
`:. phi=B.S=0.2(3/5E_0)`
`=0.2xx0.6xx2xx10^3`
`=240N-m^2//C`
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