Capacitance of a conductor is `1muF`. What charge is required to raise its potential to `100 V`?
A
`300muC`
B
`200muC`
C
`10muC`
D
`100muC`
Text Solution
Verified by Experts
The correct Answer is:
D
Using the equation `q=CV` we have, `q=(1muF)(100V)` `=100muC`
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