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The electrostatic energy stored in a parallel-plate capacitor of capacitance 2muF is 10mJ. If the separation between the plates of the capacitor is 1mm, the elctric field inside the capacitor is 10^(X)N//C . The value of X is_____.
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Area of a parallel plate capacitor of capacitance 2F and separation between the plates 0.5cm will be
The plate area of a parallel-plate capacitors is 10cm^(2) and its capacitance is 2pF . The separation between the plates of the capacitors is close to (in mm). (permittivity of vacuum, epsi_(0)=(80)/(9)xx10^(-12)m^(-3)kg^(-1)s^(4)A^(2),1pF=10^(-12)F )
