In the circuit shown in figure, find the steady state charges on oth the capacitors.
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Current in the upper circuit `i_1=10/(3+2)=2A` `:. V_(BG)=V_B-V_G=3i_1=3xx2=6V` current in the lower circuit `i_2=20/(4+6)=2A` `V-(CF)=V_C-V_F=4i_2=4xx2=8V` Charge on both the capacitors will be same. Let it be q. Applying Kirchoff's second law in loop BGFCB, `=6-a/(6xx10^-6)+8-q/(3xx10^-6)=0` or `((10^6)q)/2=2` `or q=4xx10^-6C` `or q=4muC`
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