Two conductors of capacitance `1muF` and `2muF` are charged to `+10V` and `-20 V` They are now connected by a conducting wire. Find
(a) their common potential
(b) the final charges on them
(c) the loss of energy during, redistribution of charges.

Explanation

`q_1=C_1V_1=10muC`
`q_2=C_2V_2=-40muC`
a. ` V=q_(Total)/C_(Total)=(-30muC)/(3muF)=-10vol t`
b. `q_1^'=C_1V` and `q_1^'=C_2V`
c. `/_\U=(C_1C_2)/(2(C_1+C_2)(V_1-V_2)^2`