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A parallel air capacitance 245muF has a ...

A parallel air capacitance `245muF` has a charge of magnitude `0.48muC` on each plate. The plates are `0.328 mm` apart.
(a) What is the potential difference between the plates?
(b) What is the area of each plate?
(c) What is the surface charge density on each plate?

Text Solution

Verified by Experts

`a. V=q/C`
b. `C=(epsilon_0A)/d`
`:. A=(Cd)/epsilon_0`
`c. sigma=q/A`
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Knowledge Check

  • One plate of a capacitor of capacitance 2muF has total charge +10muC and its other plate has total charge +40mUC . The potential difference between the plates is (in Volt).

    A
    7.5
    B
    15
    C
    25
    D
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  • If Q is the charge on the pates of a capacitor of capacitances C,V the potential difference between the plates, s the area of each plate and d the distance between the plates, the force of attraction between the plates is-

    A
    `(1)/(2)((Q^(2))/(epsilon_(0)A))`
    B
    `(1)/(2)((CV^(2))/(d))`
    C
    `(1)/(2)((CV^(2))/(Aepsilon_(0)))`
    D
    `(1)/(4)((Q^(2))/(piepsilon_(0)d^(2)))`
  • In an isolated parallel plate capacitor of capacitance C , the plates have charge Q_(1) and Q_(2) . The potential difference between the plates is

    A
    `(Q_(1)+Q_(2))/(2C)`
    B
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