A capacitor of capacity `2muF` is charged to `100 V`. What is the heat ( in mili joule ) generated when this capacitor is connected in parallel to n another capacitor of same capacity?

Answer

5

Explanation

`q=CV=200muC`
In parallel the common potential is given by
`V=("Total charge")/("Total capacity")`
`=(200muC)/((2+2)muF)=50V`
Heat loss=`U_i-U_f`
`=1/2(2xx10^-6)(100)^2-1/2(4xx10^-6)(50)^2`
`=5xx10^-3J`
`=5mJ`