The dielectric to be used in a parallel-plate capacitor has a dielectric constant of 3.60 and a dielectric strength of `1.60 xx 10^7 V//m`. The capacitor is to have a capacitance of `1.25 xx10^-9F` and must be able to withstand a maximum potential difference of `5500 V`. What is the minimum area the plates of the capacitor may have?

Answer

A, B, C

Explanation

`d=V_(max)/E_(max)`
`C=(Kepsilon_A)/d`
`:. A=(dC)/(Kepsilon_0)=((V_(max))(C))/((K)(E_(max))(epsilon))`