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A circuit has section AB as shown in fig...

A circuit has section `AB` as shown in figure. The emf of the source equals `E=10V`, the capacitor capacitances are equal to `C_1 =1.0muF` and `C_2=2.0muF`, and the potential difference `V_A-V_B=5.0V`. Find the voltage across each capacitor.

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Verified by Experts

The correct Answer is:
A

`q` shown in figure is in `muC`
Now` V_A-1/1+10-q/2=V_B`
or `V_A-V_B-(3q)/2-10=5`
`:. q=10muC`
Now, `V=q/C` across each capacitor.
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DC PANDEY-CAPACITORS-Exercise
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