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The plates of a parallel-plate capacitor...

The plates of a parallel-plate capacitor in vacuum are `5.00 mm` apart and `2.00 m^2` in area. A potential difference of `10,000 V` is applied across the capacitor. Compute
(a) the capacitance
(b) the charge on each plate, and
(c) the magnitude of the electric field in the space between them.

Text Solution

Verified by Experts

The correct Answer is:
A, B, C
a.`C=(epsilon_0A)/d`
b. `q=CV`
c. `E=V/d`
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DC PANDEY-CAPACITORS-Exercise
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