Find the charges on `6muF ` and `4muF` capacitors

Answer

C, D

Explanation

If we see the charge on positive plate of `6muF` capacitor then
`q_2=-q_1-(q_4-q_3)` ………..i
Now applying three loop equations we have
`5-q_1/3+q_2/6=0`…………..ii
`10-q_2/6-q_3/2=0`….iii
`5-q_3/2-q_4/4=0`.......iv
Solving these four equations we can find `q_1,q_2,q_3` and `q_4`