A capacitor of capacitance `C_1 = 1.0muF` charged upto a voltage `V = 110 V` is connected in parallel to the terminals of a circuit consisting of two uncharged capacitors connected in series and possessing the capacitance `C_2 = 2.0 muF` and `C_3 = 3.0muF`. What charge will flow through the connecting wires?

Answer

C

Explanation

`C_23=(2xx3)/(2+3)=1.2muF`
` q_("total")=C_1V=110muC`
Common potential in parallel is given by
`V=("Total charge")/("Total capacity")`
`=110/(1+1.2)=50V`
`q_23=(C_23)V=60muC`
So, this much charge flows through the switch.