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A capacitors C1 is charged to a potentia...

A capacitors `C_1` is charged to a potential `V` and connected to another capacitor in seris with a resistor `R` as shown. It is observed that heat `H_1` is dissipated across resistance `R`, tilll the circuit reaches steady state. Same process is repeated using resistance of `2R`. If `H_2` is heat dissipated in this case then

A

`H_2/H_1=1`

B

`H_2/H_1=4`

C

`H_2/H_1=1/4`

D

`H_2/H_1=2`

Text Solution

Verified by Experts

The correct Answer is:
A
`H_1=H_2=U_i-U_f`
the only change is by increasing the resistance `tau_C` increase. Hence process of radistribution of charge slows down.
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DC PANDEY-CAPACITORS-Exercise
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  8. A capacitor of capacitance C is charged to a potential difference V fr...

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  10. In the circuit shown in the figure, switch S is closed at time t=0. Se...

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  12. In the circuit shown, A and B are equal resistances. When S is closed,...

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  14. In the circuit shown each capacitor has a capcitance C. The emf of the...

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  16. A parallel plate capacitor is charged and then the battery is disconne...

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  17. A capacitor of 2F (practically not possible to have a capacity of 2F) ...

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  18. given that potential differene across 1muF capacitor is 10V. Then,

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