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In the circuit shown switch S is closed ...

In the circuit shown switch `S` is closed at `t=0`. Let `i_1` and `i_2` be the current at any finite time t then the ratio `i_1/i_2`

A

is constant

B

increases with line

C

decrease with time

D

first increases then decreases

Text Solution

Verified by Experts

The correct Answer is:
B
`i_1=(V/(2R))e^(-t/(6CR))`
`:. i_2=(V/R)e^(-t/(CR))`
`:. i_1/i_2=e^((5t)/(6CR))/2`
we can that this ratio is increasing with time.
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