Find the potential difference between points `M` and `N` of the system shown in figure, if the emf is equal to `E = 110 V` and the capacitance ratio `C_1/C_2 is 2`.

Answer

A, C

Explanation

Applying loop law in two closed loops, we have
`110-q_2/C+(q_1-q_2)/C=` or `q_2=(110C)`
and `-110+q_1/(2C)+(q_1-q_2)/C=0`
`or q_1=((440C)/3)`
potential difference between points `M` and `N` is
`V_N-V_m=(q_1-q_2)/C`
`=110/3` volt