In the given circuit diagram, find the charges which flow through directions 1 and 2 when switch `S` is closed.

Answer

A, B, C

Explanation

Let us first find charges on both capacitors before and after closing the switch

`q_2=EC_2=q_1=0`
`q_0=E((C_1C_2)/(C_1+C_2))`
From `2-q_0` charge will flow so that charge on right hand side plate of `C_1` becomes zero. From 1, `q_2` charge will flow.