The charge on the capacitor is initially zero. Find the charge on the capacitor as a function of time `t`. All resistors are of equal value `R`.

Answer

A, B, C

Explanation

Circuit can be drawn as shown in figure ltbr. In charging of capacitor `R_3` has no role.
In steady state, potential difference acorss capacitor =potentiasl difference across `R_2=E/2`
Therefore , steady state charge across capacitor
`q_0=(CE/2)`
To find time constant of cirucit we will have to short circuit the battery, then we will find net resistance across capacitor.
`R_(n et)=R/2implies tau_C=CR_(n et)=(CR)/2`
`:.` Charging in the capacitor at time t would be
`q=q_0(1-e^((-t)/tau_C)=(CE)/2)(1-e^(-(2t)/(CR)))`