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Two coils have a mutual inductance of `0.005 H`. the current changes in the first coil according to equation `I=I_0 sinomegat`, where `I_0=10A` and `omega=100pirad//s`. The maximum value of emf (in volt) in the second coil is

A

`2pi`

B

`5pi`

C

`pi`

D

`4pi`

Text Solution

Verified by Experts

The correct Answer is:
B
`(dI)/(dt)=I_0 omega cos omega t`
`e=M(dI)/(dt)=MI_0 omega cos omega t`
`:. e_(max)=MI_0 omega`
`=0.005x10xx100pi`
`=(5pi)V`
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