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A magnetic flux through a stationary loo...

A magnetic flux through a stationary loop with a resistance `R` varies during the time interval `tau` as `phi=at(tau-t)`. Find the amount of the generated in the loop during that time

A

`(atau^2)/(2R)`

B

`(a^2tau^2)/(3R)`

C

`(2a^2tau^3)/(3R)`

D

`(atau)/(3R)`

Text Solution

Verified by Experts

The correct Answer is:
B
`e=|(dphi)/(dt)|=(atau=2at)`
`i=e/R=(atau-2at)/R`
`H=int_0^taui^2Rdt`
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Knowledge Check

  • The magnetic flux through a stationary loop with resistance R varies during interval of time T as phi = at (T – t). The heat generated during this time neglecting the inductance of loop will be

    A
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    `Q=(1)/(R ).(Delta phi)/(Delta t)`
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    `Q=(Delta phi)/(R )`
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