At the instant when the current in an inductor magnitude of the self-induced emf is `0.0640 A//s`, the magnitude fo the self- induced emf is `0.0160 V`.
(a) What is the inductance of the inductor?
(b) If the inductor is a solenoid with 400 turns, what is the average magnetic flux through each turn when the current is `0.720A`?

Answer

A, B, D

Explanation

`a. L=|e/(di//dt)|=0.016/0.064=0.25H`
`b L=(Nphi)/i`
`:. =(Li)/N=((0.25)(0.72))/400`
`4.5xx10^-4Wb`