Two toroidal solenoids are wound around the same pipe so that the magnetic field of one passes through the turns of the other. Solenoid 1 has 700 turns and solenoid 2 has 400 turns. When the current in solenoid 1 is `6.52 A`, the average flux through each turn of solenoid 2 is `0.0320 Wb`.
(a) What is the mutual inductance of the pair of solenoids?
(b) When the current in solenoid 2 is `2.54 A`, what is the average flux through each solenoid 1?

Answer

A, B, C

Explanation

a. `M=(N_2phi_2)/i_2=((400)(0.032))/6.52=1.96H`
b. `M=(N_1phi_1)/i_2`
`phi_2=(Mi_2)/N_1=((1.96)(2.54))/700`
`=7.12xx10^-3Wb`