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Figure shows a conducting rod of negligi...

Figure shows a conducting rod of negligible resistance that can slide on smooth U-shaped rail made of wire of resistance `1Omega//m`. Position of the conducting rod at `t=0` is shown. A time dependent magnetic field `B=2t` tesla is switched on at `t=0`

The current in the loop at `t=0` due to induced emf is

A

`0.16A`, clockwise

B

`0.08A,` clockwise

C

`0.16A`, anti clockwise

D

zero

Text Solution

Verified by Experts

The correct Answer is:
A

`|e|=(dphi)/(dt)=S(dB)/(dt)`
`=(0.2xx0.4)(2)=0.16V`
`i=(|e|)/R=0.16/((1)(40+40+20)xx10^2)`
`=0.16A`
`o.` Magnetic field passing through the loop is increasing. So, induced curret should produce `ox` magnetic field. Hence induced current is clockwise.
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