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An AC voltage is applied acrss a series ...

An `AC` voltage is applied acrss a series combination of `L` and `R`. If the voltage drop across the resistor and inductor are `20 V` and `15 V` respectiely, then applied peak voltage is

A

`25V`

B

`35V`

C

`25sqrt2V`

D

`5sqrt7V`

Text Solution

Verified by Experts

The correct Answer is:
C
`V=sqrt(V_R^2+V_L^2)`
`=sqrt((20)^2(15)^2)=25V`
But this is the rms value.
`:.` Peak value of `=sqrt2 V_("rms")=25sqrt(2)V`.
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